arelyhernandez13
arelyhernandez13 arelyhernandez13
  • 04-09-2018
  • Mathematics
contestada

I need help on #2 please help me fast

I need help on 2 please help me fast class=

Respuesta :

Panoyin
Panoyin Panoyin
  • 04-09-2018

[tex] \frac{3ab^{2} - d^{3}}{a}[/tex]

[tex] \frac{3(-\frac{1}{2})(4)^{2} - (-3)^{3}}{-\frac{1}{2}} [/tex]

[tex] \frac{3(-\frac{1}{2})(16) + 27}{-\frac{1}{2}} [/tex]

[tex] \frac{3(-8) + 27}{-\frac{1}{2}} [/tex]

The answer is B.

[tex] \frac{-24 + 27}{-\frac{1}{2}} [/tex]

[tex] \frac{3}{-\frac{1}{2}} [/tex]

[tex] -6 [/tex]

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