amourjordyy amourjordyy
  • 03-10-2018
  • Mathematics
contestada

What is the axis of symmetry of h(x)=5x^2+40x+64

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Аноним Аноним
  • 03-10-2018

The axis of symmetry of a parabola is the vertical line passing through its vertex. Given a parabola [tex] ax^2+bx+c=0 [/tex], the vertex x-coordinate can be found using

[tex] x = -\dfrac{b}{2a} [/tex]

In your case, the formula leads to

[tex] x = -\dfrac{40}{10} = -4 [/tex]

So, this parabola is symmetric with respect to the line  [tex] x = -4 [/tex]

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