proutyhaylee
proutyhaylee proutyhaylee
  • 04-02-2019
  • Mathematics
contestada

Solve 2^x=32 and rewrite this equation in a logarithmic form

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-02-2019

Answer:

x=5

x = log2(32)

Step-by-step explanation:

2^x=32

Rewrite 32 as 2^5

2^x = 2^5

Since the bases are the same, the exponents have to be the same

x=5

2^x=32

Take log base 2 on each side

log2(2^x) = log2(32)

x = log2(32)

Answer Link

Otras preguntas

1. Someone who is young, lacks funds, and really wants to gain technical skills while serving his or her nation should consider
please help me with this problem. image attached.
name 5 consecutive integers where the middle one is 0
Vertex of f(x)=x^2+12x+8
¿De qué lengua proviene el término “Belice”? a. Africana c. Maya b. Europea d. Francesa
Help Pls. Due 10/4/18 Thank you❤️
how do solve a problem like (-5,-3); slope = -3/5 if i have to write the equation of the line with the given point and slope.
Why did warfare and internal conflict characterize the late seventeenth century
Help please number 11
if ∠2 and ∠3 are supplementary angles, then ∠2 and ∠3 form a linear pair true or false