eight divided by √6-√3 i'm not sure how to divide with radicals in the denominator.

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D2a7niechasmnidiamst D2a7niechasmnidiamst

04-07-2016
Mathematics

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eight divided by √6-√3 i'm not sure how to divide with radicals in the denominator.

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jhonyy9 jhonyy9 · Answer 1 · 2016-07-09T20:50:49+02:00

so just you need to rationalize the denominator so multiple top and bottom by conjugate so by sqrt6 +sqrt3

8 8(sqrt6 +sqrt3) 8(sqrt6 +sqrt3)
----------------- = ------------------------------------- = ----------------------- =
sqrt6 - sqrt3 (sqrt6 -sqrt3)(sqrt6 +sqrt3) 6 -3

8(sqrt6 +sqrt3)
= -----------------------
3

hope this will help you