Answer:
2.86L
Explanation:
Given parameters:
V1 Â = 2.1L
T1  = 200°C  = 200 + 273  = 473K
T 2  = 370°C  = 370 + 273  = 643K
Unknown:
V2 Â = ?
Solution:
Since pressure is constant, we apply the Charles's law;
      [tex]\frac{V1}{T1}[/tex]  =  [tex]\frac{V2}{T2}[/tex] Â
V is volume
T is the temperature
1 is the initial state
2 is the new state
        [tex]\frac{2.1}{473}[/tex]   = [tex]\frac{V2}{643}[/tex] Â
         V2  = 2.86L