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  • 03-02-2017
  • Mathematics
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jdoe0001 jdoe0001
  • 03-02-2017
[tex]\bf \measuredangle DFC=\cfrac{1}{2}(\widehat{BG}+\widehat{CD})\implies \measuredangle DFC=\cfrac{\widehat{BG}+\widehat{CD}}{2}[/tex]

you know what the arcCD is, and what the angle DFC is, so
solve for the arcBG
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