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How much of an 18% solution of sulfuric acid should be added to 360 ml of a 10% solution to obtain a 15% solution?

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owensmith6
Here is how I completed the problem:

I started by creating a ratio:

[tex] \frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}[/tex]

Where 'x' is the desired amount of the 18% solution of sulfuric acid. 

From here, I solved for 'x':

[tex] \frac{0.10x}{0.018} + \frac{360(0.18)}{0.018} = \frac{x+360}{0.15} [/tex]
[tex] \frac{0.10x}{0.018} + \frac{64.8}{0.018} = \frac{x+360}{0.15} [/tex]
[tex] \frac{0.10x+64.8}{0.018} = \frac{x+360}{0.15} [/tex]
[tex]0.15(0.10x+64.8) = 0.018(x+360)[/tex]
[tex]0.015x+9.72 = 0.018x+6.48[/tex]
[tex]0.003x = 3.24[/tex]
[tex]x = 1080[/tex]

∴You will need to add 1080ml of 18% Sulfuric Acid in order to obtain a 15% solution.

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