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Describe the relationship between the segments made when secant lines intersect outside a circle. Use the following image as reference.

Respuesta :

Let the extensions of secants AD and BC meet at point P.

Let the measure of ar DC be 2a, then m(DAC)=m(DBC)=a, since angles DAC and DBC are both inscribed angles intercepting arc DC.

m(P)=b.

Then triangles APC and BPD are similar, because they have 2 pairs of common angles.

from the similarity of APC and BPD, we can write the ratios:

[tex] \frac{AP}{BP} = \frac{PC}{PD} = \frac{AC}{BD} [/tex]
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