A sprinkler rotates through an angle of 115° spraying water outward for a distance of 12 ft. find the exact area watered, then round the result to the nearest tenth of a square foot.
The sprinkler rotates through an angle of 115° and sprinkles water outward for a distance of 12 ft. Therefore the radius of the circular section is 12 ft as shown in the diagram below.
The total circle occupies 360°. Therefore the area watered is A = (115/360)*π*(12 ft)² = 144.513 ft²
