First i notice we can get rid of X if we multiply the entire first equation by 3 so it makes it easier to add the equations toogether and get rid of X 3(3X+3Y=10) 9X+9Y=30
Next we will add this new equation (9X+9Y=30) to the other equation (-9X+9Y=30)
9X+9Y=30 + -9X+9Y=30 ---------------- 18Y=60 Then we divide both sides by 18 18Y=60 /18 /18 Y=3.3333333 Last we substitute Y=3.333 into one of the two equations to find X value 3X+3Y=10 3X+3(3.33)=10 Finally we solve for X 3X+3(3.33)=10 3X+10=10 -10 -10 3X=0 /3 /3 X=0
The answer could be (0,3.33) but the more likely answer is No Solution. These two equations represent lines and when we solve a system of equations what we are really trying to find is a point where the two lines intersect, sometimes these lines do not cross paths, due to them being parallel. The way to test this is to put these two equations into Y-intercept formula (Y=mx+b) and graph them to see if they are parallel if so this system of equations has no anwser